Identify the smallest ion among the following:

Al³⁺

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K⁺

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Mg²⁺

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Na⁺

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Solution

The correct option is A
Al³⁺

More the nuclear charge on ion, electrons are more strongly attracted and thus size decreases. Hence, among the given ions Al³⁺ is the smallest ion.

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N a^{+}, M g^{2 +}

A l^{3 +}, N a^{+}

$N a^{+} . M g^{2 +}, A l^{3 +}$ and $S i^{4 +}$ are isoelectronic. The order of their ionic size is

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S i^{4 +}

O^{2 -}, F^{-}, N a^{+}, M g^{2 +}

A l^{3 +}

N a^{+}, M g^{2 +}, A l^{3 +}

S i^{4 +}

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