Identify the solution set for 7x-5-8x-3-4-

The correct option is A ( 1725, 38) Given inequality is #160; 7x 58x+3 gt;4 On solving given equation further, we get 7x 58x+3 4 gt;0 ⇒ ...

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Standard XII

Mathematics

Greatest Integer Function

Identify the ...

Question

Identify the solution set for $\frac{7 x - 5}{8 x + 3} > 4$ .

(- \frac{17}{25}, - \frac{3}{8})

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(- \frac{5}{7}, - \frac{3}{8})

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(- \frac{31}{28}, \frac{3}{8})

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(- \frac{13}{15}, - \frac{3}{8})

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Solution

The correct option is A $(- \frac{17}{25}, - \frac{3}{8})$
Given inequality is $\frac{7 x - 5}{8 x + 3} > 4$
On solving given equation further, we get
$\frac{7 x - 5}{8 x + 3} - 4 > 0$

$\Rightarrow \frac{7 x - 5 - 32 x - 12}{8 x + 3} > 0$

$\Rightarrow \frac{25 x + 17}{8 x + 3} < 0$

If $x > - \frac{3}{8}$ , then from above equation $x < - \frac{17}{25}$ , which is not possible on number line.

If $x < - \frac{3}{8}$ , then from above equation $x > - \frac{17}{25}$ , it give us $- \frac{17}{25} < x < - \frac{3}{8}$
Therefore, $x \in (- \frac{17}{25}, - \frac{3}{8})$
Hence, option A is correct.

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Similar questions

Re-arrange suitably and find the sum in each of the following :

(i) $\frac{11}{12} + \frac{- 17}{3} + \frac{11}{2} + \frac{- 25}{2}$

(ii) $\frac{- 6}{7} + \frac{- 5}{6} + \frac{- 4}{9} + \frac{- 15}{7}$

(iii) $\frac{3}{5} + \frac{7}{3} + \frac{9}{5} + \frac{- 13}{15} + \frac{- 7}{3}$

(iv) $\frac{4}{13} + \frac{- 5}{8} + \frac{- 8}{13} + \frac{9}{13}$

(v) $\frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5}$

(vi) $\frac{1}{8} + \frac{5}{12} + \frac{2}{7} + \frac{7}{12} + \frac{9}{7} + \frac{- 5}{16}$

Evaluate :

$(i) \frac{3}{7} + \frac{- 4}{9} + \frac{- 11}{7} + \frac{7}{9} (i i) \frac{2}{3} + \frac{- 4}{5} + \frac{1}{3} + \frac{2}{5} (i i i) \frac{4}{7} + 0 + \frac{- 8}{9} + \frac{- 13}{7} + \frac{17}{9} (i v) \frac{3}{8} + \frac{- 5}{12} + \frac{3}{7} + \frac{3}{12} + \frac{- 5}{8} + \frac{- 2}{7}$

Verify the following :

(i) $\frac{3}{7} \times (\frac{5}{6} + \frac{12}{13}) = (\frac{3}{7} \times \frac{5}{6}) + (\frac{3}{7} \times \frac{12}{13})$
(ii) $\frac{- 15}{4} \times (\frac{3}{7} + \frac{- 12}{5}) = (\frac{- 15}{4} \times \frac{3}{7}) + (\frac{- 15}{4} \times \frac{- 12}{5})$
(iii) $(\frac{- 8}{3} + \frac{- 13}{12}) \times \frac{5}{6} = (\frac{- 8}{3} \times \frac{5}{6}) + (\frac{- 13}{12} \times \frac{5}{6})$
(iv) $\frac{- 16}{7} \times (\frac{- 8}{9} + \frac{- 7}{6}) = (\frac{- 16}{7} \times \frac{- 8}{9}) + (\frac{- 16}{7} \times \frac{- 7}{6})$

Q. Simplify:
(i)

\frac{11}{12} \div (\frac{5}{9} \times \frac{18}{25})

(ii)

(2 \frac{1}{2} \times \frac{8}{10}) \div (1 \frac{1}{2} + \frac{5}{8})

(iii)

\frac{15}{16}

(\frac{5}{6} - \frac{1}{2}) \div \frac{10}{11}

(iv)

\frac{9}{8} \div \frac{3}{5}

(\frac{3}{4} + \frac{3}{5})

(v)

\frac{2}{5} \div {\frac{1}{5} o f [\frac{3}{4} - \frac{1}{2}] - 1}

(vi)

(1 \frac{3}{4} \times 3 \frac{1}{7}) - (4 \frac{3}{8} \div 5 \frac{3}{5})

Prove that:
(i) $\frac{1}{3 + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{3}} + \frac{1}{\sqrt{3} + 1} = 1$
(ii) $\frac{1}{1 + \sqrt{2}} + \frac{1}{\sqrt{2} + \sqrt{3}} + \frac{1}{\sqrt{3} + \sqrt{4}} + \frac{1}{\sqrt{4} + \sqrt{5}} + \frac{1}{\sqrt{5} + \sqrt{6}} + \frac{1}{\sqrt{6} + \sqrt{7}} + \frac{1}{\sqrt{7} + \sqrt{8}} + \frac{1}{\sqrt{8} + \sqrt{9}} = 2$

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Identify the solution set for 7x−58x+3>4.

Identify the solution set for $\frac{7 x - 5}{8 x + 3} > 4$ .