Question

Identify the type of gas filled in container A and B respectively

• A. Mono, mono
• B. Dia, dia
• C. Mono, dia
• D. Dia, Mono

Answer 1

Answer: (C)

Mono, dia

Since the temperature rise and heat supplied to both the container is same.

$Q=n_A{C}_{VA}\Delta T=n_B{C}_{VB}\Delta T$ $\Rightarrow n_A{C}_{VA}=n_B{C}_{VB}-\left(1\right)$

also, $\Delta P_{A}V=n_{A}R\Delta T-\left(2\right)$

and, $\Delta P_{B}V=n_{B}R\Delta T-\left(3\right)$

Dividing $\left(2\right)$ by $\left(3\right)$,

$\frac{n_A}{n_B}=\frac{\Delta P_A}{\Delta P_B}=2.5/1.5=5/3$

$\Rightarrow n_A=5n_B/3$

From equation $\left(1\right)$

$C_{VB}/C_{VA}=5/3=\left(5R/2\right)/\left(3R/2\right)$

$C_{VB}=5R/2$, so $B$ is diatomic.

$C_{VA}=3R/2$, so $A$ is Mono-atomic.