Identify the value of tan 3-tan- in terms of a and y-

The correct option is A (3x 4)y(4 3y)x tan #160; 3θ =3sin #160; θ 4sin^3θ4cos^3θ 3cos #160; θ=tan #160; θ [ 3 4sin^2θ4cos^2θ 3 ]⇒tan 3θtan ...

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Byju's Answer

Standard XII

Mathematics

Integration by Substitution

Identify the ...

Question

Identify the value of $\frac{tan 3 θ}{tan θ}$ in terms of a and y.

\frac{(3 x - 4) y}{(4 - 3 y) x}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

\frac{(4 - 3 y) x}{(3 x - 4) y}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{(4 - 3 x) y}{(4 - 3 y) x}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

\frac{3 y}{2 x}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $\frac{(3 x - 4) y}{(4 - 3 y) x}$
$tan 3 θ = \frac{3 sin θ - 4 {sin}^{3} θ}{4 {cos}^{3} θ - 3 cos θ} = tan θ [\frac{3 - 4 {sin}^{2} θ}{4 {cos}^{2} θ - 3}] \Rightarrow \frac{tan 3 θ}{tan θ} = [\frac{3 - 4 {sin}^{2} θ}{4 {cos}^{2} θ - 3}] = \frac{3 - \frac{4}{x}}{\frac{4}{y} - 3} = \frac{(3 x - 4) y}{(4 - 3 y) x}$

Suggest Corrections

Similar questions

Q. Factorize :

2 x^{2} - 18 y^{2}

$The locus of the point of intersecion of the lines \sqrt{3} x - y - 4 \sqrt{3} γ = 0 a n d \sqrt{3} γ x + γ y - 4 \sqrt{3} = 0 i s a h y p e r b o l a o f e c c e n t r i c i t y$

Q. Subtract :

3 x^{2} + 2 y x

from

2 x^{2} + 3 y x

Identify the like and unlike terms in $4 x y, 8 x^{2}$ and $3 y x$ .

Q. The value of

(2 x - 3 y)^{3} + (x + 3 y)^{3} + 3 (2 x - 3 y)^{2} (x + 3 y) + 3 (2 x - 3 y) (x + 3 y)^{2} =

Join BYJU'S Learning Program

Identify the value of tan3θtanθ in terms of a and y.

The correct option is A (3x−4)y(4−3y)xtan3θ=3sinθ−4sin3θ4cos3θ−3cosθ=tanθ[3−4sin2θ4cos2θ−3]⇒tan3θtanθ=[3−4sin2θ4cos2θ−3]=3−4x4y−3=(3x−4)y(4−3y)x

Identify the value of $\frac{tan 3 θ}{tan θ}$ in terms of a and y.