Identify the value of limx→11−x1/31−x1/4
Let L=limx→11−x1/31−x1/4
This is 00 form, therefore by using L'Hospital rule
Therefore, L=limx→10−13x−2/30−14x−3/4
⇒L=limx→143x−2/3x−3/4⇒L=43(1)−2/3(1)−3/4⇒L=43
.Option B is correct.