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Byju's Answer
Standard XII
Chemistry
Types of Redox Reactions
Identify X in...
Question
Identify X in the equation given below.
F
e
C
l
3
+
S
O
2
+
H
2
O
→
F
e
C
l
2
+
H
C
l
+
X
A
H
2
S
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B
S
O
3
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C
H
2
S
O
4
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D
H
2
S
O
3
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Solution
The correct option is
C
H
2
S
O
4
The balanced equation can be written as:
2
F
e
C
l
3
+
S
O
2
+
2
H
2
O
→
2
F
e
C
l
2
+
2
H
C
l
+
H
2
S
O
4
Thus X =
H
2
S
O
4
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0
Similar questions
Q.
A list of reactions are given below.
(a)
F
e
+
2
H
C
l
→
F
e
C
l
2
+
H
2
(b)
F
e
S
+
2
H
C
l
→
F
e
C
l
2
+
H
2
S
(c)
F
e
+
S
Δ
−
→
F
e
S
(d)
N
a
C
l
+
H
2
S
O
4
<
200
o
C
−
−−−
→
N
a
H
S
O
4
+
H
C
l
(e)
C
u
S
O
4
+
H
2
S
→
C
u
S
+
H
2
S
O
4
(f)
S
+
H
2
S
O
4
→
3
S
O
2
+
H
2
O
Identify redox reactions.
Q.
Balance the following equation by ion electron method.
F
e
C
l
3
+
H
2
S
→
F
e
C
l
2
+
H
C
l
+
S
.
Q.
Identify the oxidant and the reductant in the following reaction respectively:
(
i
)
F
e
C
l
2
+
H
2
O
2
+
H
C
l
→
F
e
C
l
3
+
H
2
O
Q.
If :
S
+
O
2
→
S
O
2
;
Δ
H
=
−
298.2
k
J
S
O
2
+
1
2
O
2
→
S
O
3
;
Δ
H
=
−
98.7
k
J
S
O
3
+
H
2
O
→
H
2
S
O
4
;
Δ
H
=
−
130.2
k
J
H
2
+
1
2
O
2
→
H
2
O
;
Δ
H
=
−
227.3
k
J
the enthalpy of formation of
H
2
S
O
4
at
298
K will be.
Q.
If
S
+
O
2
→
S
O
2
;
Δ
H
=
−
298.2
S
O
2
+
1
2
O
2
→
S
O
3
;
Δ
H
=
−
98.7
S
O
3
+
H
2
O
→
H
2
S
O
4
;
Δ
H
=
−
130.2
H
2
+
1
2
O
2
→
H
2
O
;
Δ
H
=
−
287.3
Then the enthalpy of formation of
H
2
S
O
4
at 298 K is
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