Question

Identify $"\mathrm{X}"$in the following reaction $\underset{\mathrm{Iron}\mathrm{chloride}}{{\mathrm{FeCl}}_3\left(\mathrm{s}\right)}+\underset{\mathrm{Sodium}\mathrm{hydroxide}}{3\mathrm{NaOH}\left(\mathrm{aq}\right)}\to \mathrm{X}+\underset{\mathrm{Sodium}\mathrm{chloride}}{3\mathrm{NaCl}\left(\mathrm{s}\right)}$

Answer 1

Double displacement reaction:

1. Ferric chloride (Ironchloride) is a yellow-brown soluble inorganic compound in water.
2. Sodium hydroxide is a colorless, strong alkaline solution that produces hydroxyl ions $\left({\mathrm{OH}}^{-}\right)$ rapidly
3. Brown color precipitate is created when we add an aqueous $\mathrm{NaOH}$ solution to the aqueous ${\mathrm{FeCl}}_3$ solution. Ferric hydroxide $\mathrm{Fe}{\left(\mathrm{OH}\right)}_3$ is this precipitate.
4. The balanced reaction for this reaction is $\underset{\mathrm{Iron}\mathrm{chloride}}{{\mathrm{FeCl}}_3\left(\mathrm{aq}\right)}+\underset{\mathrm{Sodium}\mathrm{hydroxide}}{3\mathrm{NaOH}\left(\mathrm{aq}\right)}\to \underset{\mathrm{Ferric}\mathrm{hydroxide}(\mathrm{Brown}\mathrm{colour}\mathrm{ppt})}{\mathrm{Fe}{\left(\mathrm{OH}\right)}_3\left(\mathrm{s}\right)}+\underset{\mathrm{Sodium}\mathrm{chloride}}{3\mathrm{NaCl}\left(\mathrm{s}\right)}$
5. Because both the chlorine ion and the hydroxyl ion are exchanged, this is a double displacement reaction.

Therefore, $\mathrm{X}=\mathrm{Fe}{\left(\mathrm{OH}\right)}_3$ in the given reaction.