Question

Identify $X$ in the reaction.

$CHC{l}_3\underset{HF}{\overset{Sb{F}_3}{\to }}CH{F}_{2}Cl\stackrel{1070K}{\to }\left(X\right)+2HCl$

• A. $F_{2}C=C{F}_2$
• B. $ClFC=CFCl$
• C. $F_{2}C=CFCl$
• D. $F_{2}C=CC{l}_2$

Answer 1

The correct option is A $F_{2}C=C{F}_2$

When chloroform is treated with antimony trifluoride and $HF$, 2 chlorine atoms are replaced with 2$F$ atoms.

When $CH{F}_{2}Cl$ is heated to 1070 K, terafluoroethylene (compound X) is obtained.

$2CH{F}_{2}Cl\stackrel{1070K}{\to }{F}_{2}C=C{F}_2$