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Question

Identify X in the reaction.


CHCl3SbF3−−HFCHF2Cl1070K(X)+2HCl

A
F2C=CF2
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B
ClFC=CFCl
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C
F2C=CFCl
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D
F2C=CCl2
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Solution

The correct option is A F2C=CF2
When chloroform is treated with antimony trifluoride and HF, 2 chlorine atoms are replaced with 2F atoms.

When CHF2Cl is heated to 1070 K, terafluoroethylene (compound X) is obtained.

2CHF2Cl1070K−−−F2C=CF2

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