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Question

Identify X, Y, Z in the following series:


C2H5IalcKOH−−−−−→XBr2−−→YExcessofKCN−−−−−−−−−−→Z :

A
BrCH2CH2CN
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B
C2H4
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C
NCCH2CH2CN
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D
BrCH2CH2Br
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Solution

The correct options are
B C2H4
C NCCH2CH2CN
D BrCH2CH2Br
Alc. KOH is dehydrohalogenating agent so at first alkene forms which reacts further with bromine to form a dibromo product.

Then in presence of KCN, bromine is substituted by the cyanide group.

Reaction is :
C2H5Ialc.KOH−−−−C2H4(x)Br2BrCH2CH2Br(y)KCN−−CNCH2CH2CN(z)

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