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B
CH3−(CH2)4−O−CH3
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C
CH3CH2−CH−O−CH2CH3
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D
CH3−(CH2)3−O−CH2CH3
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Solution
The correct option is DCH3−(CH2)3−O−CH2CH3
Addition of HBr to alkene in presence of peroxide gives anti Markovnikov's product.
From the given option it is cleared that it undergoes substitution reaction. 1∘ alkyl halide on reaction with C2H5ONa gives SN2 reaction.