Identify $Z$ in the following sequence.

{C H}_{3} C O C l

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{C H}_{3} {C O N H}_{2}

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{C H}_{3} C O O H

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{C H}_{3} {C H}_{2} C O O H

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Solution

The correct option is D ${C H}_{3} {C H}_{2} C O O H$
$C H_{3} C H_{2} B r K C N ⟶ C H_{3} C H_{2} - C \equiv N d i l H C l ⟶ C H_{3} C H_{2} C O O H$

Alkyl bromide reacts with potassium cyanide to give Alkyl cyanide which on excess hydrolysis gives propanoic acid.

The mechanism is shown in the above image.

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The correct order of decreasing boiling points of CH₃CONH₂ (A) CH₃COCl (B) CH₃COOH (C) and (CH₃CO)₂O (D) is:

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