Identify Z in the reaction sequences.
$C H_{3} C H_{2} C H = C H_{2} H B r - -- \to H_{2} O_{2} Y C_{2} H_{5} O H - ---- \to Z$

C H_{3} (C H_{2})_{2} C H_{2} - O - C_{2} H_{5}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(C H_{3})_{3} C H - O - C_{2} H_{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} (C H_{2})_{3} C H_{2} - O - C H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C H_{2} C H (C H_{3}) - O - C_{2} H_{5}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $C H_{3} (C H_{2})_{2} C H_{2} - O - C_{2} H_{5}$
$C H_{3} C H_{2} C H = C H_{2} H B r, H_{2} O_{2} - -------------- \to anti-Markovnikov's effect C H_{3} C H_{2} C H_{2} C H_{2} B r (Y)$

$Y C_{2} H_{5} O H - ------ \to substitution C H_{3} C H_{2} C H_{2} C H_{2} - O - C_{2} H_{5} (Z)$

Suggest Corrections

Similar questions

Z

C H_{3} C H_{2} C H = C H_{2} H B r - -- \to H_{2} O_{2} Y C_{2} H_{5} O N a - ----- \to Z

C H_{3} I M g - -- \to E t h e r X i . D r y i c e - ---- \to i i H_{2} O Y C l_{2} - -- \to R e d P Z

Z

C H_{3} C H_{2} B r K C N - -- \to X d i l . H C l - --- \to Δ Z

C H_{2} = C H_{2} H B r - -- \to x A g . N a O H - ----- \to Y N a_{2} C O_{3} / E x c e s s I_{2} - ----------- \to

Z

C H_{3} C H_{2} C H_{2} O H C o n c . H_{2} S O_{4} - ------- \to 160 - 180^{o} C X B r_{2} + C C l_{4} - ------ \to Y N a N H_{2} - ---- \to Z

Join BYJU'S Learning Program