Identify $Z$ in the sequence of reactions:
$C H_{3} C H_{2} C H = C H_{2} H B r - -- \to H_{2} O_{2} Y C_{2} H_{5} O N a - ----- \to Z$

C H_{3} - (C H_{2})_{3} - O - C H_{2} C H_{3}

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

(C H_{3})_{2} C H - O - C H_{2} C H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} (C H_{2})_{4} - O - C H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

C H_{3} C H_{2} - C H (C H_{3}) - O - C H_{2} C H_{3}

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is D $C H_{3} - (C H_{2})_{3} - O - C H_{2} C H_{3}$
In the given sequence, the compound $Z$ is $C H_{3} - (C H_{2})_{3} - O - C H_{2} C H_{3}$ .
$H B r$ in presence of peroxide gives anti Markovnikoff addition product.
A molecule of $H B r$ is added across $C = C$ double bond. $B r$ is added to $C$ atom having more number of $H$ atoms. $1^{o}$ alkyl halide on reaction with $C_{2} H_{5} O N a$ gives $S_{N} 2$ reaction.
Bromide ion is replaced with ethoxide ion.

Suggest Corrections

Similar questions

C H_{3} - C H_{2} - C H (O H) - C H_{2} C H_{3} [O] \to A C H_{3} M g - I - ----- \to H_{2} O / H^{+} B

Which of the following is a metamer of $C H_{3} C H_{2} - S - C H_{2} C H_{3}$ ?

C H_{3} - C H_{3} | C H - C H_{2} - O - C H_{2} C H_{3} + H I Δ - \to ?

C H_{3} C H_{2} C H_{2} - O | | C - O - C H_{2} C H_{3}

C H_{3} C H_{2} - O | | C - O - C H_{2} C H_{2} C H_{3}

H - H | C | H - o | | C | H

C H_{3} - C H_{3} | C | B r - C H_{2} C H_{3}

Join BYJU'S Learning Program