Question

Identity the physical quantities and their units using the combination of the given units coulomb (c) joule (j) meter (m) second (s) .
a. C/s. b.J/C. c. a* b d. b/a e. d * m

Answer 1

$$\begin{gathered} \left(\mathrm{a}\right) \\ \frac{\mathrm{C}}{\mathrm{s}}=\mathrm{Current}\left(\mathrm{I}\right) \\ \left(\mathrm{b}\right) \\ \frac{\mathrm{J}}{\mathrm{C}}=\mathrm{Potential}\left(\mathrm{V}\right) \\ \left(\mathrm{c}\right) \\ \mathrm{a}\times \mathrm{b}=\mathrm{IV} \\ =\mathrm{Electrical}\mathrm{power}\left(\mathrm{P}\right) \\ \left(\mathrm{d}\right) \\ \frac{\mathrm{b}}{\mathrm{a}}=\frac{\mathrm{V}}{\mathrm{I}} \\ =\mathrm{Electrical}\mathrm{resistance}\left(\mathrm{R}\right) \\ \left(\mathrm{e}\right) \\ \mathrm{d}\times \mathrm{m}=\mathrm{ohm}-\mathrm{m} \\ =\mathrm{Resistivity} \end{gathered}$$