Identyfy oxidation and reduction process for the reaction-
$H_{2} O (s) + F_{2} (g) \to H F (g) + H O F (g)$

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Solution

Species $H$ $O$ $F$
Reactants $+ 1$ $- 2$ $0$
Product $+ 1$ $0$ (for HOF) $- 1$ (for HF and HOF)
as it is clear that oxidation of $H$ and reduction of $F$ is taking place so this is a redox reaction.
$C o n c e p t :$ increase in oxidation number is Oxidation and decrease in the oxidation number is reduction.
this is the required solution.

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