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IE1 and IE2...

Question

$I E_{1}$ and $I E_{2}$ of magnesium are $178$ and $348$ kcal/mole.

The energy for the reaction $M g_{(g)} \to M g_{(g)}^{2 +} + 2 e^{-}$ is:

+ 170

kcal

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+ 526

kcal

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170

kcal

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- 526

kcal

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Solution

The correct option is B $+ 526$ kcal
Ionisation is an endothermic process. So, the total ionisation energy for ionisation of $2$ electrons is the summation of first ionisation enthalpy and second ionisation enthalpy.

IE = $178 + 348 = 526$ K cal

Hence, the correct option is $B$

Suggest Corrections

Similar questions

$I E_{1}$ and $I E_{2}$ of Mg are 178 and 348 Kcal ${m o l}^{- 1}$ respectively. The energy required for the reaction

$M_{(g)}$ $\to$ ${M g}^{2 +}$ _(g) + 2 $e^{-}$ is

I E_{1}

I E_{2}

M g

178

348 kcal

M g \to M g^{2 +} + 2 e^{-}

I E

I E_{1}

I E_{2}

M g

178

348 kcal

M g \to M g^{2 +} + 2 e^{-}

I E

I P_{1}

I P_{2}

M g

^{- 1}

M g \to M g^{2 +} + 2 e^{-}

I E_{1}

I E_{2}

M g

178

348 kcal

M g \to M g^{2 +} + 2 e^{-}

I E

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