IE1 and IE 2 of Mg are 740-1540 kJ mol- calculate percentage of Mg - and Mg 2- if 1 g of Mg absorbs 50-0 KJ of energy-

Let x be the mole of Mg+ Let y be the mole of Mg2+ Total mole of Mg in 1 gm of Mg = 1/molar mass of Mg = 1/24 So x + y = 1/24 Energy absorb by 1 mol ...

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Byju's Answer

Standard XII

Chemistry

Conformational Isomerism

IE1 and IE 2 ...

Question

(IE)1 and (IE) 2 of Mg are 740,1540kJ mol-' calculate the percentage of Mg⁺and Mg²⁺ if 1g of Mg absorbs 50.0KJ of energy.

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Solution

Let x be the mole of Mg⁺
Let y be the mole of Mg²⁺
A total mole of Mg in 1 gm of Mg = 1/molar mass of Mg = 1/24
So x + y = 1/24
Energy absorbed by 1 mole of Mg+ = 740 KJ
So energy absorbed by x mole of Mg+ = 740x KJ
Energy absorbed by 1 mole of Mg2+ = 1540 KJ
So enegy absorbed by y mole of Mg2+ = 1540y KJ
Total energy absorbed = 50 KJ
So 740x KJ + 1540y KJ = 50 KJ
740x + 1540y = 50
74x + 154y = 5
x + y = 1/24
24x+24y = 1
74x + 154y = 5
Substitute the value of x from equation 1 to equation 2
x = (1/24 - y)
74 * (1/24 - y) + 154y = 5
154y - 74 y = 5 - 74/24
80y = (120-74)/24
80y = 46/24
y = 23/960 mole
Mass of Mg²⁺ present = 23/960 * 24 = 23/40 gm
So x = (1/24 -y)
x = 1/24 - 23/960
x = (40-23) /960
x = 17/960 mole
Mass of Mg+ present = 24 * 17/960 = 17/40 gm
Percentage of x = x/(x+y) 100 = 17/40 100 = 42.5 %
Percentage of y = 100 - 42.5 = 57.5 %
Answer : Mg⁺ = 42.5 % and Mg ²⁺ = 57.5 %

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(IE)1 and (IE) 2 of Mg are 740,1540kJ mol-' calculate the percentage of Mg+ and Mg2+ if 1g of Mg absorbs 50.0KJ of energy.

(IE)1 and (IE) 2 of Mg are 740,1540kJ mol-' calculate the percentage of Mg⁺and Mg²⁺ if 1g of Mg absorbs 50.0KJ of energy.