If $0.01$ mole of solute is present in $500 m l$ of solution, its molarity is:

0.01 M

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0.005 M

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0.02 M

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0.1 M

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Solution

The correct option is D $0.02 M$
Molarity $= \frac{N o . o f m o l e s}{V o l u m e (i n l i t r e s)}$

$= \frac{0.01}{(500 / 1000)} = 0.02 M$

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