Question

If $0.1\text{g}$ of an organic compound contains phosphorus gave $0.222\text{g of}M{g}_2{P}_2{O}_7$, then the percentage of phosphorus in the compound is:

• A. $31$
• B. $0.2$
• C. $66$
• D. $62$

Answer 1

The correct option is D $62$

$\%\text{phosphorus}=\frac{62}{222}\times \frac{\text{wt. of}M{g}_2{P}_2{O}_7}{\text{wt. of organic compound}}\times 100$
$\Rightarrow \frac{62}{222}\times \frac{0.222}{0.1}\times 100=62\%$