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Depression in Freezing Point

If 0.25 g o...

Question

If $0.25 g$ of an acid can exactly neutralise $20 m l$ of $0.125 N$ base. Equivalent weight of the acid is:

A

100

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B

40

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C

50

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D

12.5

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Solution

The correct option is A $100$
$N_{1} V_{1} = N_{2} V_{2}$
LHS is nothing but the total equivalents of the acid.
$\frac{0 \cdot 25}{e q \times w t} = 0 \cdot 125 \times \cdot 020$
$e q = \frac{0 \cdot 25}{0 \cdot 125 \times \cdot 020}$
$e q \cdot w t = 100$

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