Question

If 0.3 A current is passed through a lamp, how many electrons will pass in 60 seconds? (e = 1.6 $\times {10}^{-19}$ )

• A. 2.88 $\times {10}^{20}$
• B. 1.125 $\times {10}^{20}$
• C. 2.25 $\times {10}^{20}$
• D. 1.8 $\times {10}^{20}$

Answer 1

The correct option is B 1.125 $\times {10}^{20}$

I = 0.3 A
e = 1.6 $\times {10}^{-19}$ C
t = 60 sec
I = $\frac{Q}{t}$
$\therefore$ Q = I x t = 0.3 x 60
Q = ne
No. of electrons passing through the bulb
$n=\frac{Q}{e}=\frac{18}{1.6\times {10}^{-19}}=11.25\times {10}^{20}$ electrons