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Question

If 0.5 mole of BaCl2 is mixed with 0.2 mol of Na3PO4, the maximum amount of Ba3(PO4)3 that can be formed is:


A
0.7 mol
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B
0.5 mol
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C
0.2 mol
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D
0.1 mol
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Solution

The correct option is D 0.1 mol
BaCl2+Na3PO4Ba3(PO4)2+NaCl
Equivalents of BaCl2=0.5×nf=0.5×2=1
Equivalents of Na3PO4=0.2×nf=0.5×3=0.6
Equivalents of Ba3(PO4)2formed=0.6=moles×nf
Moles of Ba3(PO4)2=0.66=0.1 moles

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