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Limiting Reagent or Reactant

If 0.5 mole...

Question

If $0.5$ moles of $B a C l_{2}$ is mixed with $0.2$ moles of $N a_{3} P O_{4}$ , the maximum number of moles of $B a_{3} (P O_{4})_{2}$ that can be obtained is :

0.7

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0.5

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0.3

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0.1

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Solution

The correct option is D $0.1$
$3 B a C l_{2} + 2 N a_{3} P O_{4} \to B a_{3} (P O_{4})_{2} + 6 N a C l$
3 moles of $B a C l_{2}$ will react with 2 moles of $N a_{3} P O_{4}$ to form 1 mole of $B a_{3} (P O_{4})_{2}$ .
0.3 moles of $B a C l_{2}$ will react with 0.2 moles of $N a_{3} P O_{4}$ to form 0.1 mole of $B a_{3} (P O_{4})_{2}$ .

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