If $0.765$ gm of an acid gives $0.535$ gm of $C O_{2}$ and $0.138$ gm of $H_{2} O$ . Then, the ratio of the percentage of carbon and hydrogen is :

19 : 2

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18 : 12

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20 : 17

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1 : 7

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Solution

The correct option is A $19 : 2$
% $C = \frac{12}{44} \times \frac{m a s s o f C O_{2}}{m a s s o f c o m p o u n d} \times 100$
$= \frac{12}{44} \times \frac{0.535}{0.765} \times 100$
% $C = 19.07 %$
% $H = \frac{2}{18} \times \frac{M a s s o f H_{2} O}{M a s s o f c o m p o u n d} \times 100$
$= \frac{2}{18} \times \frac{0.138}{0.765} \times 100$
$H = 2.00$
Therefore, ratio of $C$ & $H$ $= \frac{19}{2}$

Option A is correct.

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