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Question

If 0x3π,0y3πandcosx.siny=1 then the possible number of values of the ordered pair (x,y) is

A
6
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B
12
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C
8
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D
15
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Solution

The correct option is A 6
cosxsiny=1
When
1) cosx=siny=1
x=2nπ and =(4n1)π2
2) cosx=siny=1
x=(2n+1)π and y=(4n+3)π2
x=0,2πy=π2,5π2 or x=πy=3π2

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