If 0 - argz -4- then the least value of -2 -2z - 4- is

The correct option is C 4 √(2)|2z 4|=2√(2)|z 2| Given that 0≤ argz≤π4 The least value of |z 2| is √(2) and occurs at argz=π4 Therefor ...

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Properties of Argument

If 0 ≤ argz...

Question

If 0 $\leq$ argz $\leq \frac{π}{4}$ , then the least value of $\sqrt{2} | 2 z - 4 |$ is

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If 0 $\leq$ Argz $\leq \frac{π}{4}$ , then the least value of $\sqrt{2}$ |2z - 4i| is

1 + sin (\frac{π}{4} + θ) + 2 sin (\frac{π}{4} - θ)

θ

f (x) = \frac{\sqrt{2} cos x - 1}{cot x - 1}, x \neq \frac{π}{4}

f (\frac{π}{4})

f (x)

x = \frac{π}{4}

f (x) = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} {(\frac{6}{5})}^{\frac{t a n 6 x}{t a n 5 x}}; 0 < x < \frac{π}{2} a + 2; x = \frac{π}{2} (1 + | c o t x |)^{\frac{b | t a n x |}{a}}; \frac{π}{2} < x < π \end{matrix}

x = \frac{π}{2}

a

b

| z - 4 + 3 i | \leq 1

m

n

| z |

k

\frac{x^{4} + x^{2} + 4}{x}

(0, \infty)

k

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