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Question

If 0x2π, 0y2π and sinx+siny=2 then the value of x+y is

A
π
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B
π2
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C
3π
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D
none of these
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Solution

The correct option is A π
We have, sinx+siny=2
but we know that maximum value of \sin x is 1
hence only solution is sinx=1 and siny=1
so in 0x2π,0y2π
solution is x=π2,y=π2
therefore,
x+y=π
Hence, option 'A' is correct.

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