If 0 < c < b <a and the roots α,β of the equation are imaginary then
(|α|+|β |)/2 =|α||β |
|α|+|β |>2
|α|+|β |<2
None of these
Since α=−b+i√4ac–b22c and β = −b+i√4ac–b22c <0
|α|=|β |=√b2+4ac−b24c2= √ac<1