If 0.¯¯¯¯¯¯27 is written in simplest fractional form pq, then find p×q.
x=0.¯¯¯¯¯¯27 ..........(I)
Here the periodicity of the decimal is two.
So multiply both sides of (i) by 100, we have
100x=27.¯¯¯¯¯¯27 ......….(II)
Subtracting (I) from (II), we get
99x=27
x=2799=311
i.e., p = 3, q = 11
So, p×q=3×11=33