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Question

If 0.¯¯¯¯¯¯27 is written in simplest fractional form pq, then find p×q.

A
35
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B
23
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C
33
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D
37
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Solution

The correct option is C 33

x=0.¯¯¯¯¯¯27 ..........(I)

Here the periodicity of the decimal is two.
So multiply both sides of (i) by 100, we have
100x=27.¯¯¯¯¯¯27 ......….(II)

Subtracting (I) from (II), we get

99x=27

x=2799=311
i.e., p = 3, q = 11
So, p×q=3×11=33


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