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Question

If 0<θ<2π, then the intervals of values of θ for which 2sin2θ5sinθ+2>0, is

A
(0,π6)(5π6,2π)
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B
(π8,5π6)
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C
(0,π6)(π6,5π6)
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D
(41π48,π)
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Solution

The correct option is A (0,π6)(5π6,2π)
R.E.F image
2sin2θ5sinθ+2>0
or 2sin2θ(sinθ2)1(sinθ2)>0
2sinθ(sinθ2)1(sinθ2)>0
or (sinθ2)(2sinθ1)>0
or sinθ2 will be always -ve
ar |sinθ|
(2sinθ1)<0
sinθ<12
θϵ(0,π/6)(5π6,2π)
(A) wrong option

1067974_1138651_ans_9a38f96b7bd0479dbad2e21d56d03cbb.JPG

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