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Question

If 0 < x < 1, the number of solutions of the equation tan1(x1)+tan1x+tan1(x+1)=tan13x is

A
\N
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B
1
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C
2
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D
3
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Solution

The correct option is B 1
The given equation can be written as
tan1(x1)+tan1(x+1)=tan13xtan1x2x2x2=2x1+3x2x+3x3=2xx34x3x=0(4x21)=0x=0,x=±12.Thusx=12

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