If 0 < x < 1, the number of solutions of the equationtan−1(x−1)+tan−1x+tan−1(x+1)=tan−13x is
A
\N
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B
1
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C
2
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D
3
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Solution
The correct option is B 1 The given equation can be written as tan−1(x−1)+tan−1(x+1)=tan−13x−tan−1x⇒2x2−x2=2x1+3x2⇒x+3x3=2x−x3⇒4x3−x=0⇒(4x2−1)=0⇒x=0,x=±12.Thusx=12