The correct option is B 13.5
In the given range, the numbers sinx,cosx and cosec2x are all positive.
∴AM≥GM
⇒sinx+cosx+cosec2x3≥(sinx.cosx.cosec2x)13
⇒sinx+cosx+cosec2x≥3(sinx.cosx.12sinx.cosx)13=3213
⇒(sinx+cosx+cosec2x)3≥(3213)3=272
Hence, option B is correct