If 0-x-y then limn-yn-xn1-n-

The correct option is C y lim_n→∞(y^n+x^n)^1/n =y ×lim_ n→∞ #160;(1+( x y )^ n )^ 1/n =y ×lim_ n→∞ #160;(1+ 1 (y/x)^ n )^ 1/n ...

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Factorization Method Form to Remove Indeterminate Form

If 0<x<y th...

Question

If $0 < x < y$ then $lim n \to \infty (y^{n} + x^{n})^{1 / n} =$

1

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y

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e

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Solution

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Similar questions

0 < x < y

{lim}_{n \to + \infty} {(y^{n} + x^{n})}^{1 / n}

0 < x < y,

{lim}_{n \to \infty} {(y^{n} + x^{n})}^{1 / n}

^{n}

y_{n} = n! [l o g x + 1 + \frac{1}{2} + \frac{1}{3} . . . . + \frac{1}{n}]

\forall n ϵ N

a = \sum_{n = 0}^{\infty} x^{n}, b = \sum_{n = 0}^{\infty} y^{n}, c = \sum_{n = 0}^{\infty} (x y)^{n}

| x |, | y | < 1

y (n) = e^{x} e^{x^{2}} . . . e^{x^{n}}, 0 < x < 1

lim n \to \infty \frac{d y (n)}{d x}

x = \frac{1}{2}

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