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Question

If 0<x<y then limn+(yn+xn)1/n

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Solution

(xn+yn)1n=y(1+n)1htakefixedii<δE[E=xy]Enδ,forallnN1<(1+En)1n(1+δ)1nfornNlimx(1+δ)1n=1,limx1nln(1+δ)=0limx(xn+yh)1n=ylimx(1+δ)=y

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