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Basic Inverse Trigonometric Functions

If 00< x <90∘...

Question

If 0⁰ < x < 90^o and cos then log₁₀ sin x + log ₁₀ cos x + log ₁₀ tan x is equal to

A

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B

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C

1

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D

-1

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Solution

The correct option is D
-1

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{log}_{10} sin x + {log}_{10} cos x = - 1

{log}_{10} (sin x + cos x) = \frac{{log}_{10} n - 1}{2}

, then the value of

\frac{n}{3}

{log}_{10} sin x + {log}_{10} cos x = - 1

{log}_{10} (sin x + cos x) = \frac{({log}_{10} n - 1)}{2}

then the value of 'n/3' is

{log}_{10} sin x + {log}_{10} cos x = - 1

{log}_{10} (sin x + cos x) = \frac{{log}_{10} n - 1}{2}

, then the value of

\frac{n}{3}

f (x) = |x - 3| and g (x) = f o f (x)

, then for x > 10, g ' (x) is equal to
(a) 1
(b) −1
(c) 0
(d) none of these

{log}_{10} sin x + {log}_{10} cos x = - 1

{log}_{10} (sin x + cos x) = \frac{1}{2} ({log}_{10} n - 1) .

n .

(correct answer + 3, wrong answer 0)

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