If 09/12/2001 happens to be Sunday, then 09/12/1971 would have been at

Wednesday

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Tuesday

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Saturday

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Thursday

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Solution

The correct option is D Thursday
$09 / 12 / 2001 \to$ Sunday
No. of days between $9 / 12 / 1971$ and $9 / 12 / 2001$
As we know that every year has $1$ odd days and a leap year has 2 odd days
Therefore,
No. of normal years $= 22$
No. of leap years $= 8$
Therefore,
Odd days $= 22 + (2 \times 8) = 38 = 7 \times 5 whole weeks + 3 odd days$
Hence there are $3$ odd days in between $9 / 12 / 1971$ and $9 / 12 / 2001$ .
Hence $9 / 12 / 1971$ would have been Thurshday.

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