If 1.00 mol of each of the following compounds is dissolved in water, which one will produced maximum number of ions ? Assume that dissociation is complete.

[C u {(N H_{3})}_{4}] S O_{4} . H_{2} O

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K_{4} [F e {(C N)}_{6}]

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[C r {(H_{2} O)}_{6}] {(N O_{3})}_{3}

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K [P t C l_{3} (C_{2} H_{4})]

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Solution

The correct option is B $K_{4} [F e {(C N)}_{6}]$
One mole of these compound gives, $[C u (N H_{3})_{4}] S O_{4} . H_{2} O$ 2 ion (one complex ion + one sulphate ion).
$K_{4} [F e (C N)_{6}]$ 5 ion (4 $K^{+}$ + one complex ion).
$[C r (H_{2} O)_{6}] (N O_{3})_{3}$ 4 ion (3 nitrate +one complex ion).
$K [P t C l_{3} (C_{2} H_{4})]$ 2 ion (one $K^{+}$ + one complex ion).

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If 1.00 mol of each of the following compounds is dissolved in water, which one will produced maximum number of ions ? Assume that dissociation is complete.

The correct option is B K4[Fe(CN)6]One mole of these compound gives, [Cu(NH3)4]SO4.H2O 2 ion (one complex ion + one sulphate ion).K4[Fe(CN)6] 5 ion (4 K+ + one complex ion).[Cr(H2O)6](NO3)3 4 ion (3 nitrate +one complex ion).K[PtCl3(C2H4)] 2 ion (one K+ + one complex ion).