Question

If $1,1,\alpha$ are the roots of $x^3-6x^2+9x-4=0$ then find $\alpha$.

• A. $4$
• B. $3$
• C. $2$
• D. $5$

Answer 1

The correct option is A $4$

Comparing the given equation with $a_0{x}^3+a_1{x}^2+a_{2}x+a_3=0$, we get,
$a_0=1$, $a_1=-6$, $a_2=9$, $a_3=-4$
Product of roots $\mathrm{1.1.}\alpha =S_3=\frac{-a_3}{a_0}=\frac{4}{1}$
$\therefore \alpha =4$.