Question

If $(1-100),(101-200),(201-300),(301-400),(401-500)$ and $(501-600)$ are the class intervals of a frequency distribution, then the true class width is

• A. $99$
• B. $99.5$
• C. $100$
• D. $100.5$

Answer 1

The correct option is C $100$

Class width is the number of points in the class interval.
class width $=$ upper limit $-$ lower limit
The limits are not continuous, hence they are taken as average of upper limit of preceding class and lower limit of succeeding class.
Upper limit for second class $=\frac{200+201}{2}=200.5$
Lower limit for second class $=\frac{100+101}{2}=100.5$
Class width $=200.5-100.5=100$