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Question

If 1=111abca2b2c2, 2=1bca1cab1abc, then

(a) 1+2=0
(b) 1+2 2=0
(c) 1=2
(d) none of these

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Solution

(a) 1+2=0

Δ2 =1 bc a1 ca b1 ab c=1abca abc a2b bca b2c cab c2 [R1, R2, R3 are multiplied by a, b and c respectively, therefore we divide by abc]=abcabc a 1 a2b 1 b2c 1 c2 Taking abc common from C2=-1 a a21 b b21 c c2 C1C2We know that the value of a determinant remains unchanged if its rows and columns are interchanged. So,2=-1 1 1a b ca2 b2 c2 =-Δ1Δ1+ Δ2 = 0

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