If $1^{2} + 2^{2} + 3^{2} + . . . . . . + 2003^{2} = (2003) (4007) (334)$ and $(1) (2003) + (2) (2002) + (3) (2001) + . . . . . + (2003) (1) = (2003) (334) (x) . .,$ then x equals

2005

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2004

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2003

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2001

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Solution

The correct option is A $2005$

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Similar questions

Q. If

1^{2} + 2^{2} + 3^{2} + . . . . . . . + 2003^{2} = (2003) (4007) (334)

and

(1) (2003) + (2) (2002) + (3) (2001) + . . . . . + (2003) (1) = (2003) (334) (x)

., then x equals

Q. If

(1) (2003) + (2) (2002) + (3) (2001) + \dots + (2003) (1) = (2003) (334) (x),

then the value of

[\frac{x}{5}]

is equal to
([.] represents the greatest integer function)

Q. Sum of the series

S = 1^{2} - 2^{2} + 3^{2} - 4^{2} + . . . . . - 2002^{2} + 2003^{2}

Q. The number of days a hillside city received snow in different years.

Year	$2003$	$2004$	$2005$	$2006$
Days	$8$	$10$	$5$	$12$

If $\frac{1}{1^{2}} + \frac{1}{2^{2}} + \frac{1}{3^{2}} + . . . \infty = \frac{π^{2}}{6}$ , then $\frac{1}{1^{2}} + \frac{1}{3^{2}} + \frac{1}{5^{2}} +$ .... equals

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If 12+22+32+......+20032=(2003)(4007)(334) and (1)(2003)+(2)(2002)+(3)(2001)+.....+(2003)(1)=(2003)(334)(x).., then x equals

The correct option is A 2005

If $1^{2} + 2^{2} + 3^{2} + . . . . . . + 2003^{2} = (2003) (4007) (334)$ and $(1) (2003) + (2) (2002) + (3) (2001) + . . . . . + (2003) (1) = (2003) (334) (x) . .,$ then x equals

The correct option is A $2005$