If [1 2 3] A = [4 5], the order of matrix A is
3 x 2
3 x 1
2 x 3
2 x 1
If order of matrix A is m × n and order of matrix B is n × p then,
order of AB = m × p, Here
Order of [1 2 3] = 1 × 3
Order of [4 5] = 1 × 2
∴ Order of A is 3 × 2
Solve for a: 3×12+6a+2=29
In ΔABC, right angled at B, if cot A = √3 then the value of cos A x sin C + sin A x cos C =