If 1+2+3+⋯+k=N2 and N is less than 100, then the value of k can be (where N ∈ Natural numbers)
A
8
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B
1 and 49
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C
8 and 36
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D
both (a) and (b)
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Solution
The correct option is D both (a) and (b) Go through options 1+2+3+⋯+k=N2 (a perfect square) k(k+1)2=N2 1×22=(1)2→ a perfect square number, 8×92=4×9=(2×3)2→ a perfect square number. and 49×502=49×25=(7×5)2→ a perfect square number.