If (1,2,4) and (2,−3λ,−3) are the initial and terminal points of the vector i+5j−7k, then the value of λ is
A
73
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B
−73
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C
−53
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D
53
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E
−75
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Solution
The correct option is C−73 Let OA=i+2j+4k and OB=2i−3λj−3k Given, AB=i+5j−7k ⇒OB−OA=i+5j+7k ⇒i+(−3λ−2)j−7k=i+5j−7k On comparing the coefficient of j, we get −3λ−2=5 ⇒λ=−73