If (1, 2), (4, y), ( x, 6) and (3, 5) vertices of a parallelogram taken in order. Find x and y
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Solution
Let (1,2), (4,y), (x,6) and (3,5) are the coordinates of A,B,C,D vertices of a parallelogram ABCD, intersection point of diagonal AC and BD also divides these diagonals. Therefore, O is the mid-point of AC and BD. If O is the mid-point of AC, then the coordinates of O are (1+x2,2+62)⇒(frac1+x2,4) If O is the mid-point of BD, then the coordinates of O are (4+32,5+y2)⇒(72,5+y2) Since bothe the coordinates are of the same point O, ∴frac1+x2=frac72and4=frac5+y2 ⇒x+1=7and5+y=8 ⇒x=6andy=3