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Question

If 1, 2, α are the roots of the equation 2x3+x27x6=0, then find α.

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Solution

Fact: If α,β,γ are the roots of ax3+bx2+cx+d=0, then
α+β+γ=ba
αβ+βγ+γα=ca
and αβγ=da

So if 1,2,α are the roots of 2x3+x27x6=0, then

1+2+α=12
α=121=32

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