Question

If $1.2$ g of a metal displaces $1.12$ L of hydrogen at NTP, equivalent mass of the metal would be:

• A. $1.2\times 11.2$
• B. $12$
• C. $24$
• D. $1.2+11.2$

Answer 1

The correct option is B $12$

Given that

$W_M=1.2g$
$V_{H_2}=1.12L$

Now,

$E=\frac{W_M\times 11.2}{V_{H_2}}=1.2\times \frac{11.2}{1.12}=12g$