Question

If $1.2$ g of metal displaces $1.12$ L of hydrogen at normal temperature and pressure, an equivalent weight of the metal would be:

• A. $12$
• B. $24$
• C. $11.2$
• D. $1.2$

Answer 1

The correct option is A $12$

$Equivalentweight=\frac{\text{Weight of the metal}}{\text{Volume of hydrogen gas liberated at STP}}\times 11.2$

$=\frac{1.2\times 11.2}{1.12}$

$=12$