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Modern Periodic Table

If 1/2 X2O(s)...

Question

If 1/2 X2O(s)--> X(s) + 1/4O2(g); H = 90kJ Then heat change during reaction of metal X with one mole of O2 to form oxide to maximum extent is 1) 360kJ 2) -360 3) -180 4) +180

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\frac{1}{2} X_{2} O_{(s)} \to X_{(s)} + \frac{1}{4} O_{2 (g)}; Δ H = 90 K J

O_{2}

M^{x +} + M n O_{4}^{-} \to M O_{3}^{-} + M n^{2 +} + \frac{1}{2} O_{2}

M n O_{4}^{-}

M^{x +}

M O_{3}^{-}

1

A r

2

C O_{2}

3

O_{2}

4

N_{2}

O_{2}

O_{2}

x^{\circ} =

x

=

In the above figure, which one of the following is not true ( $c ∥ d, a ∥ b$ )?

(a) $∠ 1 + ∠ 5 = 180^{\circ}$
(b) $∠ 2 + ∠ 5 = 180^{\circ}$
(c) $∠ 3 + ∠ 4 = 180^{\circ}$
(d) $∠ 2 + ∠ 3 = 180^{\circ}$

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